| Author | Comment |
me2
Goliath
Posted: 20 Oct 2008
11:58 GMT
Total Posts: 171 | me2labs is establishing a math group. If you are interested in joining, please let me know by e-mailing me at analystjr@aol.com. If you have any questions, please post them in this topic and the group will answer them if possible.
I will begin by *sigh* solving the problem of 1+1=X
What does X equal?
1 is a unit.
2 is a pair of units.
1+1 (a pair of units)=2 (another pair of units)
See, it's very simple. Yet so many make this question so hard. If you need help with any problem, from preschool to string physics, ask here.
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<--- Going out with a bang. |
gulyman
Goliath
Posted: 24 Oct 2008
14:27 GMT
Total Posts: 144 | I have a math problem that was on one of my tests. I had to solve it algebraically
the logs are base 10 by default
(x-2)log4=2log6
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Vectris
Ultralisk
Posted: 24 Oct 2008
14:50 GMT
Total Posts: 375 | Guly what math class are you in? We just went over logs again in our pre-calculus class, just thought it was cool -.-
Here are the only 2 ways I know, you have to have a calc for both though. If they don't let you use a calc your screwed.
1)))))
just put it into the calculator, divide 2log6 by log4 and then add 2.
2)))))
the long way, you have to condense it first, to this:
log4^(x-2) = log6^2
then cancel out the logs
4^(x-2) = 36
and then the only way I know how to solve it from here is by graphing and finding the intersection. Your x coordinate of the intersection is your answer.
If you can't use a calc then my 2nd method has the right first steps, but then from the graphing part I don't know what you can use in place, you could guess and check what x is except it's a huge decimal so it'd be a waste of time.
Since this is me2s help forum, I'll ask him.
@me2 Can you solve the above problem by hand? |
gulyman
Goliath
Posted: 24 Oct 2008
19:03 GMT
Total Posts: 144 | I live in Alberta so my math classes probably aren't anything like the ones in the states. I'm in the highest of the three grade 12 math classes my school offers.
Pure Math 10, 20, 30(I'm in this one)
Applied Math 10, 20, 30
Math 14 (for the math illiterate)
I looked in my math book and it didn't have an example that had logs on both sides. I'll ask my teacher on Monday.
@me2: what would joining the math group mean you were responsible for? |
coolethan
Marine
Posted: 24 Oct 2008
19:15 GMT
Total Posts: 27 | yes gulyman i think i had trouble on that question too and i couldn't get it so i just put "x does not equal..." and then put in all the wrong answers i got from the four different ways i tried to solve it. haha should be interesting to see what teach says on monday |
Vectris
Ultralisk
Posted: 24 Oct 2008
19:30 GMT
Total Posts: 375 | What happened to my post!!! Did you guys read it? As long as you can use a calc solving that is a cinch. |
coolethan
Marine
Posted: 29 Oct 2008
14:30 GMT
Total Posts: 27 | ya we had to solve it algebraically so you couldn't just rely on the calc for everything |
Vectris
Ultralisk
Posted: 29 Oct 2008
14:40 GMT
Total Posts: 375 | Well my first post did tell you how to get to:
4^(x-2) = 36
By using simple algebra methods, solving it algebraically as you put it.
Here's the rest.
Turn that back into a log base 4 by swapping (x-2) with 36 so:
Log(base 4)36 = x - 2
then add 2 to both sides:
[Log(base 4)36] + 2 = x
And there you go, I forgot how to do logs but you now know what x equals so there you go. |
Zachary940
Wraith
Posted: 29 Oct 2008
18:32 GMT
Total Posts: 714 | @coolethan
Because once you get into college some proffesors won't let you use your graphing calculator.
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It is much easier to suggest solutions when you know nothing about the problem. |
coolethan
Marine
Posted: 3 Nov 2008
19:05 GMT
Total Posts: 27 | for what i'm going to college for i probobly won't be needing my calculator at all actually except maybe just to program with to keep my fingers busy. i'm taking an audio engineering course or recording studio guy thing for music. |
Zachary940
Wraith
Posted: 3 Nov 2008
19:37 GMT
Total Posts: 714 | LOL, yes you are going to want your calculator. Especially for some of the math classes.
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It is much easier to suggest solutions when you know nothing about the problem. |
me2
Goliath
Posted: 6 Nov 2008
12:41 GMT
Total Posts: 171 | The first method is correct. The second method should not be used. A common scientific or engineering calculator (cost 20-30 dollars)can solve this problem.
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<--- Going out with a bang. |
