| Author | Comment |
erdeky
Probe
Posted: 8 Jul 2011
09:50 GMT
Total Posts: 6 | Is there a way to make (-1)^(1/3) display -1 instead of 1/2 + (sqrt(3)/2)i ? |
haveacalc
Guardian
Posted: 10 Jul 2011
23:15 GMT
Total Posts: 1111 | Do you want it to show the result as an expression, e.g. 3√ ̅-1̅, or are you looking to intentionally display an incorrect answer?
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-quoted directly from most movies that don't exist (and some that do). |
erdeky
Probe
Posted: 11 Jul 2011
08:00 GMT
Total Posts: 6 | Not looking for that expression, but
since (-1)^3 = -1, I am looking the real cube root of (-1) and not the principal one which the TI-89 gives.
I see that in the TI-89 ( (-1)^(1/3) )^3 = -1.
Joe |
haveacalc
Guardian
Posted: 12 Jul 2011
21:21 GMT
Total Posts: 1111 | It sounds like you're aware that roots of negative numbers are often complex, having both a real and an imaginary part. If you haven't done so already, you'll need to set your calculator to accept complex numbers by pressing the [MODE] button and changing the complex format option to rectangular.
If you're looking to get the real and complex parts separately, use real( and imag(.
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-quoted directly from most movies that don't exist (and some that do). |
