| Author | Comment |
Chris Zoba
Probe
Posted: 7 Jan 2003
06:39 GMT
Total Posts: 4 | How do you find cubed root and like the fourth root on the 89? I cant figure out how to do it :( |
Barrett
Administrator
Posted: 7 Jan 2003
14:45 GMT
Total Posts: 1676 | the cube root of 27 is the same as saying 27^(1/3), and the square root of 9 is the same thing as saying 9^(1/2). just do "to the power of the reciprocal" (but be sure that it's in parenthesis or order of operations will do 9^1 = 9 divided by 2=4.5 instead of 3.
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-Barrett A |
Chris Zoba
Probe
Posted: 8 Jan 2003
04:29 GMT
Total Posts: 4 | Ahh! I knew that, duh. Lol thanks for reminding me :) |
Chris Zoba
Probe
Posted: 9 Jan 2003
04:31 GMT
Total Posts: 4 | Ok now another problem. I want to get it back in radicall form, and I dont know how. I got somethign like 2^(2/3) and that wouldnt actually be a cubed root. So is there an easier way? THanks |
